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2828dfc870
Comments about error coming from setting PHP Directive Display Errors to ON Initializing arg1, arg2, ...arg9 ='' may be useful to avoid this problem when calling the API from a script Error logic may break when you get this notifies on the response
59 lines
2.2 KiB
PHP
59 lines
2.2 KiB
PHP
<?php
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define('VESTA_CMD', '/usr/bin/sudo /usr/local/vesta/bin/');
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if (isset($_POST['user']) || isset($_POST['hash'])) {
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// Authentication
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$auth_code = 1;
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if (empty($_POST['hash'])) {
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$v_user = escapeshellarg($_POST['user']);
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$v_password = escapeshellarg($_POST['password']);
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exec(VESTA_CMD ."v-check-user-password ".$v_user." ".$v_password." '".$_SERVER["REMOTE_ADDR"]."'", $output, $auth_code);
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} else {
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$key = '/usr/local/vesta/data/keys/' . basename($_POST['hash']);
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if (file_exists($key)) {
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$auth_code = '0';
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}
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}
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if ($auth_code != 0 ) {
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echo 'Error: authentication failed';
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exit;
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}
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// Check user permission to use API
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if ($_POST['user'] != 'admin') {
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echo 'Error: only admin is allowed to use API';
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exit;
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}
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// Not Declaring arguments may cause Notifies on the response on an API Call when the Directive Dysplay errors is enabled
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// you may initialize argument arg1, arg2,... arg9 to = '' here
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// Or post the unused args to =''
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// Prepare arguments
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if (isset($_POST['cmd'])) $cmd = escapeshellarg($_POST['cmd']);
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if (isset($_POST['arg1'])) $arg1 = escapeshellarg($_POST['arg1']);
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if (isset($_POST['arg2'])) $arg2 = escapeshellarg($_POST['arg2']);
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if (isset($_POST['arg3'])) $arg3 = escapeshellarg($_POST['arg3']);
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if (isset($_POST['arg4'])) $arg4 = escapeshellarg($_POST['arg4']);
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if (isset($_POST['arg5'])) $arg5 = escapeshellarg($_POST['arg5']);
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if (isset($_POST['arg6'])) $arg6 = escapeshellarg($_POST['arg6']);
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if (isset($_POST['arg7'])) $arg7 = escapeshellarg($_POST['arg7']);
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if (isset($_POST['arg8'])) $arg8 = escapeshellarg($_POST['arg8']);
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if (isset($_POST['arg9'])) $arg9 = escapeshellarg($_POST['arg9']);
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// Run query
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exec (VESTA_CMD.$cmd." ".$arg1." ".$arg2." ".$arg3." ".$arg4." ".$arg5." ".$arg6." ".$arg7." ".$arg8." ".$arg9, $output, $return_var);
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if ((!empty($_POST['returncode'])) && ($_POST['returncode'] == 'yes')) {
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echo $return_var;
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} else {
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if (($return_var == 0) && (empty($output))) {
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echo "OK";
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} else {
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echo implode("\n",$output)."\n";
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}
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}
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}
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?>
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