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force reload fancytree node when child is not found

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This commit is contained in:
azivner
2019-01-01 18:27:36 +01:00
parent 2f1c5b29d4
commit 8785dae753
1 changed files with 16 additions and 1 deletions
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17
src/public/javascripts/services/tree.js
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@@ -83,6 +83,10 @@ async function setNodeTitleWithPrefix(node) {
node.setTitle(utils.escapeHtml(title));
}
function getNode(childNoteId, parentNoteId) {
return getNodesByNoteId(childNoteId).find(node => !parentNoteId || node.data.parentNoteId === parentNoteId);
}
async function expandToNote(notePath, expandOpts) {
utils.assertArguments(notePath);
@@ -94,7 +98,18 @@ async function expandToNote(notePath, expandOpts) {
for (const childNoteId of runPath) {
// for first node (!parentNoteId) it doesn't matter which node is found
const node = getNodesByNoteId(childNoteId).find(node => !parentNoteId || node.data.parentNoteId === parentNoteId);
let node = getNode(childNoteId, parentNoteId);
if (!node && parentNoteId) {
const parents = getNodesByNoteId(parentNoteId);
for (const parent of parents) {
// force load parents. This is useful when fancytree doesn't contain recently created notes yet.
await parent.load(true);
}
node = getNode(childNoteId, parentNoteId);
}
if (!node) {
console.error(`Can't find node for noteId=${childNoteId} with parentNoteId=${parentNoteId}`);