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Merge remote-tracking branch 'origin/optimize-tree'
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@@ -5,14 +5,15 @@ const optionService = require('../../services/options');
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const treeService = require('../../services/tree');
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function getNotesAndBranchesAndAttributes(noteIds) {
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noteIds = Array.from(new Set(noteIds));
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const notes = treeService.getNotes(noteIds);
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const notes = treeService.getNotesIncludingAscendants(noteIds);
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noteIds = notes.map(note => note.noteId);
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noteIds = new Set(notes.map(note => note.noteId));
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sql.fillNoteIdList(noteIds);
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// joining child note to filter out not completely synchronised notes which would then cause errors later
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// cannot do that with parent because of root note's 'none' parent
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const branches = sql.getManyRows(`
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const branches = sql.getRows(`
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SELECT
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branches.branchId,
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branches.noteId,
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@@ -20,28 +21,45 @@ function getNotesAndBranchesAndAttributes(noteIds) {
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branches.notePosition,
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branches.prefix,
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branches.isExpanded
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FROM branches
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FROM param_list
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JOIN branches ON param_list.paramId = branches.noteId OR param_list.paramId = branches.parentNoteId
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JOIN notes AS child ON child.noteId = branches.noteId
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WHERE branches.isDeleted = 0
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AND (branches.noteId IN (???) OR parentNoteId IN (???))`, noteIds);
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WHERE branches.isDeleted = 0`);
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const attributes = sql.getRows(`
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SELECT
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attributes.attributeId,
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attributes.noteId,
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attributes.type,
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attributes.name,
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attributes.value,
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attributes.position,
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attributes.isInheritable
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FROM param_list
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JOIN attributes ON attributes.noteId = param_list.paramId
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OR (attributes.type = 'relation' AND attributes.value = param_list.paramId)
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WHERE attributes.isDeleted = 0`);
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// we don't really care about the direction of the relation
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const missingTemplateNoteIds = attributes
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.filter(attr => attr.type === 'relation'
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&& attr.name === 'template'
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&& !noteIds.has(attr.value))
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.map(attr => attr.value);
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if (missingTemplateNoteIds.length > 0) {
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const templateData = getNotesAndBranchesAndAttributes(missingTemplateNoteIds);
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// there are going to be duplicates with simple concatenation, however:
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// 1) shouldn't matter for the frontend which will update the entity twice
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// 2) there shouldn't be many duplicates. There isn't that many templates
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addArrays(notes, templateData.notes);
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addArrays(branches, templateData.branches);
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addArrays(attributes, templateData.attributes);
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}
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// sorting in memory is faster
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branches.sort((a, b) => a.notePosition - b.notePosition < 0 ? -1 : 1);
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const attributes = sql.getManyRows(`
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SELECT
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attributeId,
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noteId,
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type,
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name,
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value,
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position,
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isInheritable
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FROM attributes
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WHERE isDeleted = 0
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AND (noteId IN (???) OR (type = 'relation' AND value IN (???)))`, noteIds);
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// sorting in memory is faster
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attributes.sort((a, b) => a.position - b.position < 0 ? -1 : 1);
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return {
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@@ -51,6 +69,16 @@ function getNotesAndBranchesAndAttributes(noteIds) {
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};
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}
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// should be fast based on https://stackoverflow.com/a/64826145/944162
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// in this case it is assumed that target is potentially much larger than elementsToAdd
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function addArrays(target, elementsToAdd) {
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while (elementsToAdd.length) {
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target.push(elementsToAdd.shift());
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}
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return target;
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}
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function getTree(req) {
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const subTreeNoteId = req.query.subTreeNoteId || 'root';
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@@ -64,25 +92,8 @@ function getTree(req) {
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JOIN treeWithDescendants ON branches.parentNoteId = treeWithDescendants.noteId
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WHERE treeWithDescendants.isExpanded = 1
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AND branches.isDeleted = 0
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),
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treeWithDescendantsAndAscendants AS (
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SELECT noteId FROM treeWithDescendants
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UNION
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SELECT branches.parentNoteId FROM branches
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JOIN treeWithDescendantsAndAscendants ON branches.noteId = treeWithDescendantsAndAscendants.noteId
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WHERE branches.isDeleted = 0
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AND branches.parentNoteId != ?
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),
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treeWithDescendantsAscendantsAndTemplates AS (
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SELECT noteId FROM treeWithDescendantsAndAscendants
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UNION
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SELECT attributes.value FROM attributes
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JOIN treeWithDescendantsAscendantsAndTemplates ON attributes.noteId = treeWithDescendantsAscendantsAndTemplates.noteId
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WHERE attributes.isDeleted = 0
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AND attributes.type = 'relation'
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AND attributes.name = 'template'
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)
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SELECT noteId FROM treeWithDescendantsAscendantsAndTemplates`, [subTreeNoteId, subTreeNoteId]);
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SELECT noteId FROM treeWithDescendants`, [subTreeNoteId]);
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noteIds.push(subTreeNoteId);
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